Bir massiv yığmağın dörd yolu

chunk([1, 2, 3, 4], 2) --> [[ 1, 2], [3, 4]]
chunk([1, 2, 3, 4, 5], 2) --> [[ 1, 2], [3, 4], [5]]
chunk([1, 2, 3, 4, 5, 6, 7, 8], 3) --> [[ 1, 2, 3], [4, 5, 6], [7, 8]]

1)

function chunk(array, size) {
    const chunked_arr = [];
    for (let i = 0; i < array.length; i++) {
      const last = chunked_arr[chunked_arr.length - 1];
      if (!last || last.length === size) {
        chunked_arr.push([array[i]]);
      } else {
        last.push(array[i]);
      }
    }
    return chunked_arr;
}

2)

function chunk(array, size) {
  const chunked_arr = [];
  let copied = [...array]; // ES6 destructuring
  const numOfChild = Math.ceil(copied.length / size); // Round up to the nearest integer
  for (let i = 0; i < numOfChild; i++) {
    chunked_arr.push(copied.splice(0, size));
  }
  return chunked_arr;
}

3)

function chunk(array, size) {
  const chunked_arr = [];
  let index = 0;
  while (index < array.length) {
    chunked_arr.push(array.slice(index, size + index));
    index += size;
  }
  return chunked_arr;
}

4)

function chunk(array, size) {
  if (!array) return [];
  const firstChunk = array.slice(0, size); // create the first chunk of the given array
  if (!firstChunk.length) {
    return array; // this is the base case to terminal the recursive
  }
  return [firstChunk].concat(chunk(array.slice(size, array.length), size)); 
}